Advanced Criminalities Assignment Example | Topics and Well Written Essays - 500 words

Advanced Criminalities - Assignment Example The amount (percentage) of ethanol in beer varies depending on brands. The amount (percentage) of ethanol in the beer that the accused can be assumed to be a particular value so that everybody reads the same script given the difference in the percentages of ethanol in beer. iv) The test results showed that the accused was not able to perform some physical activities like standing on one leg as well as walking. It is very wrong to say that the only thing, which can impair one from walking or standing on one leg, is alcohol. There are numerous factors that can make one unable to walk. Health status of a person a significant factor that can deter someone from walking or standing on one leg. The assumption, therefore, is that the accused was of good health. No. One cannot have such high percentage of alcohol in the blood with just four beer. The person must have consumed copious amounts of beer. The percentage of ethanol in the beer was 3.5%. This value is very low and, therefore, four beers cannot result in recording 0.17% blood alcohol level. The person may have consumed four beers as he claims but might have also consumed other additional drinks, which may be responsible for the o.17% blood alcohol level. The range of maximum blood alcohol level at which one is allowed to operate a vehicle on a public road is in most states is 0.5- 0.8 for males and 0.25-0.7 for females. The blood alcohol concentration mostly depends on the gender, the period over which the alcohol was taken, the amount of food present in the stomach, the weight as well as the metabolism rate. However, it is always important to note that in as much as the BAC level of a person can be estimated, the number of drinks, height and weight alone cannot help in determining the BAC. (Zernig, Salaria, Kurz, 2000. Pg. 420) Eight 4-ounce glasses of wine with approximately 12% alcohol content would be required to make the BAC level to be 0.17%.  Ã‚